A certain shade of blue has a frequency of 7.08×1014 Hz. What is the energy of exactly one photon of this light? Planck's constant ℎ=6.626×10−34 J⋅s.

We have the final answer as

Explanation:

To find the energy of a photon of this light we use the formula

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question

f = 7.08×10¹⁴ Hz

We have

E = 7.08×10¹⁴ × 6.626 × 10-³⁴

We have the final answer as

Hope this helps you

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

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