How many grams of H3PO4 would be needed to produce 25.0 grams of H2O?

653 gH³PO⁴

Explanation:

We'll first write the chemical equation for this reaction:

P

4

O

10

(

s

)

+

6

H

2

O

(

l

)

→

4

H

3

PO

4

(

a

q

)

Let's now find the relative number of moles of phosphoric acid (

H

3

PO

4

) using the coefficients of the equation, and the fact that

10.0

mol H

2

O

react:

10.0

mol H

2

O

(

4

l

mol H

3

PO

4

6

mol H

2

O

)

=

6.67

mol H

3

PO

4

Now, using the molar mass of

H

3

PO

4

(calculated to be

98.00

g/mol

), let's find the theoretical mass of phosphoric acid produced:

6.67

l

mol H

3

PO

4

(

98.00

l

g H

3

PO

4

1

mol H

3

PO

4

)

=

653

mol H

3

PO

4

Thus, if the reaction goes to completion, there will be a yield of

653

grams of phosphoric acid

Thank me later

Mark me as brainliest please for my answer

your answer would be “dry”