A 500-g SAMPLE OF A METAL REQUIRES 20.25 kJ TO CHANGE ITS TEMPERATURE FROM 25 C TO ITS MELTING TEMPERATURE, 300 C. WHAT IS THE SPECIFIC HEAT OF THIS METAL?

ill try to . no promises tho.

explanation:

the correct answer is:

a. formation of precipitation

so she was walking and she stepped on warm jeffy , uh uh uhh dadye i just pooped my pants

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied