At 600. K how many moles of gas are in a 1.00 L cylinder at atmospheric pressure?

The number of mole of the gas present in the cylinder is 0.02 mole

From the question given above, the following data were:

Temperature (T) = 600 K

Volume (V) = 1 L

Pressure (P) = 1 atm

The number of mole of the gas present in the cylinder can be obtained by using the ideal gas equation (PV = nRT) as illustrated below:

Temperature (T) = 600 K

Volume (V) = 1 L

Pressure (P) = 1 atm

Gas constant (R) = 0.0821 atm.L/Kmol

1 × 1 = n × 0.0821 × 600

1 = n × 49.26

Divide both side by 49.26

Thus, 0.02 mole of the gas is present in the cylinder.

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0.02moles

Explanation:

To answer this question, the general gas law equation is used. The General gas law is:

Pv = nRT

Where; P = standard atmospheric pressure (1 atm)

V = volume (L)

n = number of moles

R = Gas law constant

T = Temperature

For this question; volume = 1.00L, atmospheric pressure (P) = 1 atm, R = 0.0821 L-atm / mol K, T = 600K, n = ?

Therefore; Pv = nRT

n = PV/RT

n = 1 × 1/ 0.0821 × 600

n = 1/49.26

n = 0.0203moles

Hence, there are 0.02 moles of gas.

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