Normally the capital ÎGo° for a reaction would be determined at standard temperature with each reactant at a concentration of 1 M. Letâs assume that the 1 M 2-PG solution will reach the same equilibrium ratio that would be observed under standard conditions. The enzyme enolase catalyzes the conversion of 2-PG to phosphoenolpyruvate (PEP) in living systems. You find that when you add enolase to your 2-PG solution it reaches an equilibrium with 0.68M PEP and 0.32 M 2-PG. What is the capital ÎGo° for this reaction? Use R= 1.987 cal/mol. K

a. +559 cal/mol
b. - 559 cal/mol
c. +379 cal/mol
d.-379 cal/mol

d.-379 cal/mol

Explanation:

ΔG = ΔG⁰ + RT ln K

for equilibrium ΔG = 0

ΔG⁰ + RT ln K =0

ΔG⁰   =  -  RT ln K

PG ⇒ PEP

K = [ PEP ] / [ PG ]

= .68 / .32

= 2.125

ΔG⁰   =   - 1.987 x 273 x  ln 2.125

= - 409 Cal / mole

Option d is the nearest answer .

astronomers such as edwin hubble.

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-