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Pure copper may be produced by the reaction of copper (I) sulfide with oxygen gas:

Cu2S (s) + O2 (g) --> 2Cu (s) + SO2 (g)

If 3-kg of copper (I) sulfide reacts with excess oxygen, what mass of copper metal may be produced??

If 3-kg of copper (I) sulfide reacts with excess oxygen, 3.9 kg of copper metal may be produced.

Let's consider the following balanced equation for the obtaining of pure copper.

Cu₂S(s) + O₂(g) ⇒ 2 Cu(s) + SO₂(g)

The molar mass of Cu₂S is 95.61 g/mol. The moles corresponding to 3 kg (3000 g) of Cu₂S are:

The molar ratio of Cu₂S to Cu is 1:2. The moles of Cu obtained from 31 moles of Cu₂S are:

The molar mass of Cu is 63.55 g/mol. The mass corresponding to 62 moles of Cu is:

If 3-kg of copper (I) sulfide reacts with excess oxygen, 3.9 kg of copper metal may be produced.

You can learn more about stoichiometry here: link

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)