answer : (a) volume of the gas = 8.67 ×
l
(b) second virial coefficient b = -1.21226 l/mole
solution : given, t = 300k
p = 20atm
z = 0.86
n = 8.2 mmoles = 8.2 ×
moles
r = 0.082 l atm/k/mol
find, (a) volume of gas and (b) second virial coefficient b at 300k.
formula used : ![z=\frac{pv}{nrt}](/tex.php?f=z=\frac{pv}{nrt})
and
(a)
![v=\frac{znrt}{p}](/tex.php?f=v=\frac{znrt}{p})
=
\times 0.082\times 300}{20}[/tex]
= 8.67 ×
l
(b) ![z=1+\frac{b}{v}](/tex.php?f=z=1+\frac{b}{v})
![b=(z-1)v](/tex.php?f=b=(z-1)v)
= (0.00867-1) × 8.659
= - 8.5839 l/mole