If 1.75 g of titanium metal reacts with 1.25 g of oxygen gas to form titanium (IV) oxide, what is the theoretical yield of the product?

Theoretical yield is 2.92g TiO₂

Explanation:

The reaction of Ti with O₂ to produce TiO₂ is:

Ti + O₂ → TiO₂

First, we need to find moles of titanium and oxygen. As the reaction is 1:1, we can determine directly the limiting reactant, the theoretical moles of TiO₂ and thus, theoretical yield:

Moles Ti (molar mass: 47.867g/mol):

1.75g * (1mol / 47.867g) = 0.03656 moles Ti

Moles O₂ (molar mass: 32g/mol):

1.25g * (1mol / 32g) = 0.0390 moles O₂

That means only 0.03656 moles of Ti will react withe 0.03656 moles of O₂ producing 0.03656 moles of TiO₂

As molar mass of TiO₂ is 79.866g/mol, the theoretical yield of the product is:

0.03656 moles TiO₂ * (79.866g / mol) = 2.92g TiO₂

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