Show a numerical setup for calculating the quantity of heat in joules required to completely vaporize 102.3 grams of H2O(l) at 100°C and 1.0 atm.

The heat required to vaporize 102.3 grams of H₂O(l) is 231198 J.

Explanation:

The heat required to vaporize 102.3 g of H₂O(l) can be calculated as follows:

Where:

q: is the heat  

ΔHv: is the heat of vaporization of water = 2260 J/g

m: is the mass = 102.3

Therefore, the heat required to vaporize 102.3 grams of H₂O(l) is 231198 J.

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atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer