A sample of neon gas occupies 0.220L at 0.860 atm. what will be the volume at 0.288 atm

The final volume of neon gas is 0.657 L

Explanation:

Given data:

Initial volume of neon gas = 0.220 L

Initial pressure = 0.860 atm

Final volume = ?

Final pressure = 0.288 atm

Solution:

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

0.860 atm × 0.220 L = 0.288 atm × V₂

V₂ = 0.1892 atm. L/ 0.288 atm

V₂ = 0.657 L

it is a good conductor

explanation: