A mystery element’s mass spectrum shows it to be 13.92 % Isotope A (219 amu), 72.16 % Isotope B (222 amu), and 13.92 % Isotope C (225 amu).
a. What is the atomic weight of the element?

b. What is the element?

The given element is Radon because its atomic weight is 222 amu.

Explanation:

Given data:

Percentage of A-219 = 13.92%

Percentage of B-222 = 72.16%

Percentage of C-225 = 13.92%

Atomic weight of element = ?

Solution:

Average atomic mass = (abundance of A isotope × its atomic mass) +(abundance of B isotope × its atomic mass) + (abundance of C isotope × its atomic mass)  / 100

Average atomic mass  = (13.92×219)+(72.16×222) + (13.92×225)/100

Average atomic mass =  3048.48 + 16019.52 +3132/ 100

Average atomic mass  = 22200 / 100

Average atomic mass  = 222 amu.

The given element is Radon because its atomic weight is 222 amu.

pure water does not conduct electricity very well. however, when certain substances are dissolved in water, the solution does conduct electricity. you can make a simple device that shows how well a solution conducts electricity. this device uses a flashlight bulb to indicate how well the solution conducts electricity. the better the solution conducts electricity, the brighter the bulb will glow.

explanation: