A given volume of methane diffuses in 20 seconds How long will it take the same volume of sulphur (IV) oxide to
diffuse under the same condition
(Methane = 16, Sulphur (IV) oxide=64)

Explanation:

Relative molecular mass of CH4 = 12 * 1 + 4 = 16

Relative molecular mass of SO2 = 32 + 10 *2 = 64

tSO2/tCH4 = √MSO2/MCH4

t/20 = √64/16 = √4

t/20 = 2

∴ t = 20 * 2 = 40sec

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.

the dissociation of nickel hydroxide is follows:

the concentration of hydroxide ion is

the equilibrium constant value of nickel hydroxide is = 6.1 * 10^-^1^6 and thus equilibrium equation can be written as:

thus, concentration of ni is 0.23 * 10^-^4 mol /l