Rubidium has two naturally occurring isotopes: 85Rb, with mass 84.9118 amu and natural abundance 72.15%; and 87Rb, with mass 86.9092 amu and natural abundance 27.85%. Calculate the atomic mass of rubidium. View Available Hint(s) Rubidium has two naturally occurring isotopes: 85Rb, with mass 84.9118 amu and natural abundance 72.15%; and 87Rb, with mass 86.9092 amu and natural abundance 27.85%. Calculate the atomic mass of rubidium. 86.3529 amu 84.9118 amu 85.9105 amu 85.4681 amu

85.4681  amu

Explanation:

We shall take weighted average of isotopes

Atomic mass of Rubidium

= 61.26386 + 24.2042122

= 85.4681  amu .

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.