How many Aluminum ions are in 4.5 moles of aluminum oxide?

Hat means that 12 g of Al2
2
O3
3
contain 12 g / 101.96 g mol−1
−
1
= 0.118 moles of Al2
2
O3
3
.

Each Al2
2
O3
3
formula unit contains two Al3+
3
+
ions, so there are 2 x 0.118 mol = 0.235 moles of Al3+
3
+
ions.

If you want an actual number, you can multiply that by Avogadro’s constant: 0.235 mol x 6.022 x 1023
23
mol−1
−
1
= 1.42 x 1023
23
ions.

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !