What is The pH and pOH of a 1.00x10-3M solution of CH3COOH (Ka=1.75x10-5) ?

Explanation:

Since is a weak acid to find the pH of we use the formula

where

Ka is the acid dissociation constant

c is the concentration

From the question

Ka of = 1.75 × 10^-5

c = 1.00 × 10-³M

Substitute the values into the above formula and solve for the pH

That's

We have the answer as

To find the pOH we use the formula

pH + pOH = 14

pOH = 14 - pH

pOH = 14 - 3.9

We have the answer as

Hope this helps you

hypostyle hall;