A solution is 5.00% potassium chloride by mass. How much potassium chloride would you expect to collect by evaporating 150.0 g of the solution?

C. 7.50g

Explanation:

The percent (%) by mass of a solute in a solution refers to the number of grams contained in 100g of solution by that solute. In this case, 5% by mass of pottasium chloride (KCl) means 5g of KCl is contained in 100g of solution.

Therefore, in 150g of solution, there would be:

5g/100g × 150g

= 0.05 × 150

= 7.50g of KCl solute.

Hence, 7.50g of pottasium chloride would be expected to be collected by evaporating 150.0 g of the solution.

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