A student stirs a cup of hot chocolate with a cold metal spoon and observes that the spoon becomes warmer. According to the law of conservation of energy, which answer choice best describes why the spoon became warmer? The high-energy hot chocolate particles transfer some of their energy to the spoon particles, which causes the spoon to become warmer. The high-energy spoon particles destroy some of the hot chocolate particles, which causes the spoon to become warmer. The high-energy hot chocolate particles destroy some of the spoon particles, which causes the spoon to become warmer. The high-energy spoon particles transfer some of their energy to the hot chocolate particles, which causes the spoon to become warmer.

The high-energy hot chocolate particles transfer some of their energy to the spoon particles, which causes the spoon to become warmer.

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.