Calculate the whole-number ratio of staggered to eclipsed conformers that are present at room temperature. Use the Actual G˚ barrier to rotation of -12,133.6J/mol to solve for Keq in the equation G˚= -RTln Keq. You must work with temperature in K and energy in joules. (R = 8.314 J•K-1•mol-1; T = 25 ºC = 298 K)

The ratio of staggered to eclipsed conformers is 134

Explanation:

It is possible to determine the ratio of staggered to eclipsed conformers of a reactant, using the equilibrium:

Staggered ⇄ Eclipsed

Keq = [Eclipsed] / [Staggered]

That means Keq is equal to the ratio we need to find:

Using:

G˚= -RTln Keq

Where G° = -12133.6J/mol

R is gas constant: 8.314J/molK

T is absolute temperature: 298K

-12133.6J/mol= -8.314J/molK*298K ln Keq

4.8974 = ln Keq

134 = Keq = [Eclipsed] / [Staggered]

The ratio of staggered to eclipsed conformers is 134

It will fall off and tip over. 

So what you would do is go through and add 3 teaspoons(tsp) 6 times because of the 6 tablespoons(tbsp). which will give you an answer of 18. another way is to multiply 3x6=18.