Part A The table shows the diameters of the planets in our solar system. Assume that a basketball whose diameter is 25
centimeters represents the planet Jupiter. Find the scale (ratio) between Jupiter and the basketball. Then use this ratio to
find the scaled diameter of the other planets. Enter these numbers into the table. (Saturn has been done for you.) Finally,
choose a real-world spherical or nearly spherical object that matches the scaled diameter of each planet.
Saturn is shown as an example. To find what Saturn's size would be after adjusting it to scale, follow these steps. Let the
scaled diameter of Saturn be d centimeters. If Jupiter's diameter, 142,984 kilometers, is scaled to 25 centimeters, Saturn's
diameter of 120,536 kilometers will be scaled to about 21 centimeters:
142.984 120,536
25
d
120,536x25
d
142.984
d 21 cm

Ineed someone to see if my answers are correct! if any are wrong let me know what the correct answers would be and how to get that answer! 1. how many moles of sodium chloride are in 28 grams od nacl? a. 265 mole naclb. 856 mole naclc. 479 mole of nacld. 1.2 mole nacl < my choice2. 734 grams of lithium sulfate (li2so4) are dissolved to make 2500 ml of solution what is rhe molaratiy? a. 2.67 mb. 4.56 mc. 3.89 m < my choiced. 1.78 m3. how many grams of cacl2 would be dissolved in 3.0 l of a 0.50 m solution of cacl2? a. 250 g cacl2 b. 166.5 g cacl2c. 113.65 g cacl2d. 98 g cacl2 < my choice4. suppose you had 58.44 g of nacl and you dissolved it in exactly 2.00 liters. the molarity if the solution would be 0.5 mtrue < my choicefalse 5. i would need 22g of naoh to make a 3.0 m solution using 250 ml of solvent. true < my choicefalse6. identify the solute: you have a .0195 m solution made from using 6.5 g of solute and 3 l of solvent. identify the solute by solving for molar weight. a. the solute is nacl because the molar weight is 58.43 g/mol < my choiceb. the solute is h2so4 because the molar weight is 98.06 g/molc. the solute is cacl2 because the molar weight is 111.11 g/mol

Asample of air with a volume of 2.20m3 at a pressure of 105 kpa and a temperature of 30c is cooled to 10c and the pressure is reduced to 75.0 kpa. what is the new volume? 6.9 1.34 2.56 43.0 2.88

What is one real world example of a colligative property?