A 3.689 g object is added to 7.29 mL of water causing The water level to rise to 8.54 ML. What is the density of the object? Round your final answer to two decimal places

2.95 g / mL

Explanation:

For this problem, we will simply use the equation that density is equivalent to mass over volume.  We are given the mass of the object and the initial and final volumes of water in the cylinder.  Thus we can find the density as such:

Density = Mass / ( Final Volume - Initial Volume )

Density = 3.689 g / ( 8.54 mL - 7.29 mL )

Density = 3.689 g / ( 1.25 mL )

Density = 2.9512 g / mL

Hence, the density of the object is 2.9512 g / mL.

Cheers.

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.

16

explanation:

the marks go by 4s