Pick any carboxylic acid of 4 carbons or more, and show how to convert it to the aldehyde via:

Explanation:

The fourth member of a carboxylic acid is known to be butanoic acid.

The reaction between the conversion of butanoic acid to butanal undergoes a reduction process.

At the initial stage, butanoic acid reacts with socl₂ (thionyl chloride) to form an aryl chloride known as butyryl chloride. However, the final stage proceeds by a reduction reaction where butyryl chloride is being treated with a mild reducing agent called Lithium tri-tert-butoxyaluminium hydride (LiAlH(O-t-Bu)₃ to form butanal.

The two reaction stages can be seen from the image attached below.

i think it's letter a.