The reaction of nitrogen dioxide with fluorine 2 NO2 + F2The reaction of nitrogen dioxide with fluorine 22 NO2F
is first order in NO2 and first order in F2.
Complete the rate law for this reaction in the box below.
Use the form k[A]m[B]n... , where '1' is understood for m, n ... (don't enter 1) and concentrations taken to the zero power do not appear.
Rate =
In an experiment to determine the rate law, the rate constant was determined to be 1.58E-4 M-1s-1. Using this value for the rate constant, the rate of the reaction when [NO2] = 2.84 M and [F2] = 3.60 M would be Ms-1.

Rate = 0.001615 Ms-1

Explanation:

2 NO2 + F2 --> 2 NO2F

The reaction is first order with respect to NO2 and also first order with respect to F2.

The rate law is given as;

Rate = k [NO2] [ F2]

k = 1.58E-4 M-1s-1

[NO2] = 2.84 M

[F2] = 3.60 M

Rate = ?

Inserting the values into the equation, we have;

Rate = 1.58E-4 * 2.84 * 3.60

Rate = 0.001615 Ms-1

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.