2.) In a series of experiments, a chemist prepared three different compounds that contain only iodine and fluorine. He then determined the mass of each element in each compound and found the following to be true. Compound Mass of I Mass of F 1 4.75 3.56 2 7.64 3.43 3 9.41 9.86 a.) Calculate the mass of fluorine per gram of iodine in each compound:

compound 1 = 0.749gF / 1.0gl

compound 2 = 0.4489gF / 1.0gl

compound 3 = 1.047gF / 1.0gl

Explanation:

Given that;

compound       mass of iodine in grams          mass of fluorine in grams

       1                              4.75                                             3.56

       2                             7.64                                             3.43

       3                             9.41                                              9.86

a) Calculate the mass of fluorine per gram of iodine in each compound:

- compound 1

mass of Fluorine = (3.56gF / 4.75gF) * 1.0gl

= 0.749gF

Now RATIO = 0.749gF / 1.0gl

- compound 2

mass of Fluorine = (3.43gF / 7.64gF) * 1.0gl

= 0.4489gF

Now RATIO = 0.4489gF / 1.0gl

- compound 3

mass of Fluorine = (9.86gF / 9.41gF) * 1.0gl

= 1.047gF

Now RATIO = 1.047gF / 1.0gl

"hydrogen bonding is the attraction of h atoms in the water molecule (slight + charge) to o atoms in a neighboring water molecule (slight - charge); it is a weak interatomic force. but it is still strong enough to the water molecules "stick" together."