.Which of the following is most likely to cause a change in genetic traits in an isolated population of a ground-dwelling lizard species? *
a .The exposure of an individual lizard in the population to radiation that causes a
mutation that is not passed on to its offspring.
b. An unusual dry summer in the lizards population's ecosystem.
c. The introduction on an invasive preditor that preys on the brightest-colored individuals
in the lizard population.
d. A fast-moving wildfire that burns the canopy of the tress in the lizards population
ecosystem

Theoretical temperature at which molecules stop moving and no more heat can be removed from the object. kelvin: absolute zero degrees. none of the above.

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

The answer would be true

The answer is tea due to the main ingredient being a herb that grows from the ground and sugar that grows from a stalk, i hope this : )     p.s.  can i be brainliest?