Chemistry, 08.09.2020 22:01 yasherebernalgoxa5kc

5. The reaction of hydroiodic acid and potassium hydrogen carbonate produce potassium iodide, which is used as a dietary supplement to prevent the iodine-deficiency disease, goiter. Water and carbon dioxide are by-
products.
HI + KHCO3 → KI + H2O + CO2
a. How many grams of potassium iodide are produced when 481 g of hydroiodic acid and 318 g of
potassium hydrogen carbonate react?

Answers: 3

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Answers

Answer from: AnaiyaKirksey8

Approximately $527\; \rm g$ .

Explanation:

Look up relative atomic mass data on a modern periodic table:

$\rm H$ :

. $\rm I$ : 126.904

. $\rm K$ : 39.098

. $\rm C$ : 12.011

. $\rm O$ : 15.999

Calculate the formula mass of $\rm HI$ and $\rm KHCO_3$ (the two reactants,) as well as $\rm KI$ (the product.)

$M(\mathrm{HI}) \approx 1.008 + 126.904 =127.912\; \rm g \cdot mol^{-1}$ . $M(\mathrm{KHCO_3}) \approx 39.098 + 1.008 + 12.011 + 3 \times 15.999 = 100.114\; \rm g \cdot mol^{-1}$ . $M(\mathrm{KI}) \approx 39.098 + 126.904 = 166.002\; \rm g \cdot mol^{-1}$

The question states that $m(\mathrm{HI}) = 481\; \rm g$ while $m(\mathrm{KHCO_3}) = 318\; \rm g$ . Calculate the number of moles of formula units in each of these two reactants:

$\begin{aligned} n(\mathrm{HI}) &= \frac{m(\mathrm{HI})}{M(\mathrm{HI})} \\ &\approx \frac{481\; \rm g}{127.912\; \rm g \cdot mol^{-1}} \approx 3.76\; \rm mol\end{aligned}$ .

$\begin{aligned} n(\mathrm{KHCO_3}) &= \frac{m(\mathrm{KHCO_3})}{M(\mathrm{KHCO_3})} \\ &\approx \frac{318\; \rm g}{100.114\; \rm g \cdot mol^{-1}} \approx 3.18\; \rm mol\end{aligned}$ .

Note that in the balanced equation of this reaction, the ratio between the coefficients of $\rm HI$ , $\rm KHCO_3$ , and $\rm KI$ is 1:1:1 .

Therefore, for every mole of $\rm HI$ formula units consumed, one mole of $\rm KHCO_3$ formula units will also be consumed, while one mole of $\rm KI$ formula units will be produced.

Similarly, for every mole of $\rm KHCO_3$ formula units consumed, one mole of $\rm HI$ formula units will also be consumed, while one mole of $\rm KI$ formula units will be produced.

Assume that $\rm HI$ is in excess. If all these (approximately) $3.76\; \rm mol$ of $\rm HI\!$ formula units are consumed, $3.76\; \rm mol\!$ of $\rm KHCO_3$ formula units will also need to be consumed. However, that's not possible because there was only approximately $3.18\; \rm mol$ of $\rm KHCO_3\!$ formula units available.

On the other hand, if $\rm KHCO_3$ is in excess, all these (approximately) $3.18\; \rm mol$ moles of $\rm KHCO_3$ formula units would be consumed. At the same time, approximately $3.18\; \rm mol\!$ of $\rm HI$ would be consumed- which is indeed possible because approximately $3.76\; \rm mol$ of $\rm HI\!$ formula units are available. Therefore, up to approximately $3.18\; \rm mol\!\!$ of $\rm KI$ formula units will be produced.

Calculate the mass of that $3.18\; \rm mol\!\!$ of $\rm KI$ formula units:

$\begin{aligned}m(\mathrm{KI}) &= n(\mathrm{KI}) \cdot M(\mathrm{KI}) \\ &\approx 3.18\; \rm mol \times 166.002\; \rm g \cdot mol^{-1} \approx 527\; \rm g\end{aligned}$ .

Answer from: Quest

wher is the rest of the question

Answer from: Quest

explanation:

two years ago, when picking flowers in the mountains back of yosemite valley, i found a book. it was blotted and storm-beaten; all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however; many of the inner pages were well preserved. and although all were more or less stained and torn, whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today; its granite pages have been torn and blurred by the same storms that wasted the castaway book.

two years ago, when picking flowers in the mountains back of yosemite valley; i found a book. it was blotted and storm-beaten, all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however, many of the inner pages were well preserved. and although all were more or less stained and torn; whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today, its granite pages have been torn and blurred by the same storms that wasted the castaway book.