Beryllium-8 decays through the release of an alpha particle. Draw what the nucleus would look like after an alpha particle is emitted. What element does it become?

Explanation:

Beryllium-8,⁸Be, undergoes alpha decay through the equation shown below

₄⁸Be - ₂⁴He ⇒ ₂⁴He

Hence, after an alpha decay, beryllium becomes alpha particle (helium) itself with it's nucleus shown in the attached picture. Generally, beryllium undergoes a double alpha decay as shown in the reaction below

₄⁸Be ⇒ ₂⁴He + ₂⁴He

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong