You begin with 13.89 grams of CO(g) and 17.83 grams of O 2(g) . If 14.84 grams of CO 2(g) are produced, what is the percent yield? 2 CO(g)+ 1 O 2(g) → 2 CO 2(g)"

Explanation:

2CO + O2 2CO2

from the conservation of  mass law

mass of CO2 = ( 17.83 + 13.89)= 31.72 g

% yields = Experimental mass / theoretical  mass )x 100%

            =  14.84/31.72 ) x100%

              46.78%

the answer to this question is 3.

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.