A balloon with volume of 2.0l is filled with gas at 3 atmosphere. If the pressure were reduced to 0.5 atmosphere without the change in temperature, what would be the volume of the balloon?

12L

Explanation:

To find the correct volume of the balloon, we can use the mathematical representation of Boyle’s law which states that a gas’s volume is inversely proportional to its pressure (as one increases the other decreases).

The equation for it is P1 * V1 = P2 * V2 where P1 and V1 represent the initial pressure and volume of the gas and P2 and V2 represent its changed temperature and volume.

In this case, the initial pressure of the gas inside the balloon is 3atm while its initial volume is 2.0L. Its pressure is then reduced to 0.5atm.

If we apply this information to the equation for Boyle’s law, we get
2L * 3atm = 0.5atm * V2.

Through arithmetic, we find that
6 = 0.5atm * V2
6/0.5atm = V2
12L = V2.

So, the volume of the balloon is 12L.

Hope this helps!