Neon atoms are known to produce a mass spectrum that consists of three peaks at m/z values of 20, 21 and 22, with the relative abundance of the peaks found to be in the ratio 112:0.21:11.1. Assuming the z value of the species causing the peaks to be +1 in each case, calculate the average atomic mass of neon based on these data.

Explanation:

m / z = 20 , 21 , 22

m / 1 = 20 , 21 , 22

m = 20 , 21 , 22 .

ratio of isotopes = 112 : 0.21 : 11.1

Average atomic mass = (112 x 20 + .21 x 21 + 11.1 x 22) / (112 + .21 + 11.1 )

=  (2240 + 4.41 + 244.2) / 123.31

= 2488.61 / 123.31

= 20.18

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the   per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:                   1 - α               α               α           = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

=  

or,

or,   = (at v = 1l)

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:               (1 - α)/0.5           α/0.5         α/0.5       = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

or,  

=  

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%