The percent composition by mass of an unknown chlorinated hydrocarbon was found to be 37.83% C, 6.35% H, and 55.83% Cl by mass. What is the empirical formula of this compound?

C2H4Cl

Explanation:

The first step in obtaining the empirical formula is to divide the percent by mass of each element by its relative atomic mass;

C- 37.83/12, H- 6.35/1, Cl- 55.83/35.5

3.15, 6.35, 1.57

Divide through by the lowest ratio

3.15/1.57, 6.35/1.57, 1.57/1.57

2, 4, 1

Hence, empirical formula is C2H4Cl

narendra modi is currently the pm of india

explanation:

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.