What is the empirical formula of an oxide of chromium that is 48% oxygen

Explanation:

Hello,

In this case, considering that the compound is 48% oxygen, we infer it is 52% chromium, therefore, by using their atomic masses we compute the moles by assuming those percentages as masses:

Next, by dividing by the smallest moles, we find the subscripts in the empirical formula:

Which are also expressed in the smallest whole numbers, therefore the empirical formula is:

Which corresponds to the chromic oxide or chromium (IV) oxide.

Regards.

b. accuracy of the data matters alot more than its number of digits, organization or amount of detail. quantitative observation is more accepted than the qualitative observation.