Draw the structure of a molecule which contains only carbon and hydrogen atoms (only three of which are carbon) and in which two of the carbons are sp2 hybridized and the other is sp hybridized.

CH₂ = C = CH₂

Explanation:

Hybridization is the mixing and blending of two or more pure atomic orbitals (s, p and d) to form two or more hybrid atomic orbitals that are identical in shape and energy e.d sp, sp², sp³, sp³d, sp³d² etc.

The structure of the organic molecule that contains only carbon and hydrogen atoms where there exist only three of which are carbon and in which two of the carbons are sp2 hybridized and the other is sp hybridized can be seen below.

CH₂ = C = CH₂                  ( where the = sign represent the double bonds)

Here, The two carbons that are sp₂ hybridized are CH₂

the other carbon that is sp hybdrized is C

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.