In an electrochemical cell, electrons travel in which direction? * (a) from the anode to the cathode through the external circuit (b) from the anode to the cathode through the porous cup (c) from the cathode to the anode through the external circuit (d) from the cathode to the anode through the porous cup.

In an electrochemical cell, the direction which electrons travel is: (a) from the anode to the cathode through the external circuit.

Electrons can be defined as the subatomic particles of a chemical element that are negatively charged and have a magnitude of -1.

An electrochemical cell refers to a device that is capable of either generating electric current from the electrical energy released by a spontaneous redox reaction or using an electrical energy to cause chemical reactions.

Generally, an electrochemical cell is also referred to as a secondary cell and a good example is a rechargeable battery.

In Science, the direction of flow of current is usually from the anode (positive side) to the cathode (negative side) in an electrical circuit.

On a related, current is made up of electrons and as such the direction which electrons travel is usually from the anode to the cathode through the external electrical circuit.

Find more information: link

(a) from the anode to the cathode through the external circuit

Explanation:

In an electrochemical cell, there are two half cells; the oxidation half cell and reduction half cell. Oxidation typically refers to loss of electrons and reduction refers to gain of electrons.

Electrons always flow from the anode to the cathode or from the oxidation half cell to the reduction half cell.

The electrical circuit in an electrochemical cell confirms the flow of electron. Usually a light bulb is attached. The correct option is;

(a) from the anode to the cathode through the external circuit

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.