Look up the molecular weight of Lithium diisoproylamine and determine the amount of g of base needed for this experiment. Round to the hundredths place

0.72 g

Explanation:

Note that, the mass in gram of any substance is obtained from the relationship;

Mass= number of moles × molar mass

From the sequence of the reaction, the number of moles of Lithium diisopropylamide is 6.75mmol which is the same as 6.75 × 10^-3 moles

Molar mass of base= 107.1233 g/mol

Hence mass of the base is given by;

6.75 × 10^-3 moles × 107.1233 g/mol = 0.72 g

can you list the answers so i can answer

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.