You have a stock solution that is 226mg/mL and you need 10mL of a working solution that is 15mg/mL. What is the volume of stock solution will you need to dilute to have 10mL of working solution at the above concentration. State your answer to two decimals.

0.67 ml

Explanation:

According to the dilution law,

where,

= concentration of stock solution = 226 mg/ml

= volume of stock solution = ?

= concentration of working solution= 15 mg/ml

= volume of working solution= 10 ml

Putting in the values we get:

Thus volume of stock solution needed to dilute to have 10mL of working solution at the above concentration is 0.67 ml

answer:

the reaction is type of combination reaction.

explanation:

on the product side, there are 2 molecules of bonded to fe   which means one atom of fe are combined two molecules of . so, balanced chemical equation becomes :

this reaction follows the reaction type of combination reaction. a combination reaction is defined as chemical reaction in which reactants combines together to form a single product.