If the pressure of the gas in a 2.31 L balloon is 0.12 atm and the volume increases to 7.14 L, what will be the final pressure of the air within the balloon

.0388 atm

Explanation:

Since temperature is not given , we assume that it is constant . So we can apply Boyle's law . According to it

P₁ V₁ = P₂ V₂

P₁ and V₁ are pressure and temperature initially and P₂ and V₂ are pressure and volume finally .

Putting the given values

.12 x 2.31 = 7.14 x P₂

P₂  = .12 x 2.31 / 7.14

= .0388 atm .

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