The liquid 2-chloro-2,3-dimethylbutane has a density of 0.878 g/mL at 20.0°C. If a 138 gram sample of this compound is needed, what volume of the liquid at 20.0°C must be provided? volume= mL

157.2 mL

Explanation:

The following data were obtained from the question:

Density (D) of liquid = 0.878 g/mL

Mass (m) of liquid = 138 g

Volume (V) of liquid =.?

Density of a substance is simply defined as the mass of the substance per unit volume of the substance. Mathematically, it is expressed as:

Density (D) = mass /volume

D = m/V

With the above formula, we can obtain the volume of the liquid as follow:

Density (D) of liquid = 0.878 g/mL

Mass (m) of liquid = 138 g

Volume (V) of liquid =.?

D = m/V

0.878 = 138/V

Cross multiply

0.878 × V = 138

Divide both side by 0.878

V = 138/0.878

V = 157.2 mL

Therefore, 157.2 mL of the liquid must be provided.

i'm assuming that the correct answer is indeed the first one/ "a"..

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .