The radius of a aluminum atom is 143 pm. How many aluminum atoms would have to be laid side by side to span a distance of 2.36 mm?

1.65x10⁷ atoms of Al have to be laid side by side to span a distance of 2.36mm

Explanation:

We can assume Aluminium atoms as balls ordered side by side. As the radius of 1 atom is 143pm = 143x10⁻¹²m, the space that 1 atom occupies is 2 radius = 286x10⁻¹²m. That means to occupy 2.36mm = 2.36x10⁻³ you require:

2.36x10⁻³m ₓ ( 1 atom Al / 143x10⁻¹²m) =

1.65x10⁷ atoms of Al have to be laid side by side to span a distance of 2.36mm

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