How many moles are present 560.0 g of iron (lll) sulfate

1.400 mol

Explanation:

To convert grams to moles, you will need the molar mass.  The molar mass of iron(iii) sulfate is 399.88 g/mol.  Divide grams by the molar mass to find moles.

(560.0 g)/(399.88 g/mol) = 1.400 mol

There are 1.400 mol present in 560.0 g of iron(iii) sulfate.

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