Sodium hydroxide is a strong base. What is the pH in a 0.01 mol/dm3 solution?
a. pH=2
b. pH=12
c. pH=-2
d. pH=0.01 mol/dm3

b. pH=12

Explanation:

Step 1: Given data

Concentration of NaOH: 0.01 mol/dm³ = 0.01 mol/L = 0.01 M

Step 2: Write the reaction for the dissociation of NaOH

NaOH is a strong base that dissociates according to the following equation.

NaOH(aq) ⇒ Na⁺(aq) + OH⁻(aq)

The molar ratio of NaOH to OH⁻ is 1:1. Then, the concentration of OH⁻ is 0.01 M.

Step 3: Calculate the pOH

pOH = -log [OH⁻] = -log 0.01 = 2

Step 4: Calculate the pH

We will use the following expression.

pH + pOH = 14

pH = 14 - pOH = 14 -2 = 12

the equation that correctly represent the reaction for formation of ammonia is

n2+ 3h2 → 2nh3 (answer d)

1 mole of nitrogen gas (n2) react with 3 moles of hydrogen gas (h2) to form 2 moles of ammonia ( nh3). this is in a process known as haber process were iron is used as a catalyst and reaction take place that a higher temperature and pressure. the process is exothermic hence energy is released.

"the periodic table is arranged in order of atomic number."