A concentration cell is one in which both the anode and cathode are the same but with different concentrations. Calculate the cell potential with [Zn2+] = 0.10 M[Zn2+] = 0.10 M for the cathode and the [Zn2+] = 0.010 M[Zn2+] = 0.010 M for the anode?

0.029 V

Explanation:

For the given chemical reaction :

Using Nernst equation :

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature =  298 K

n = number of electrons in oxidation-reduction reaction = 2

 = standard electrode potential of the cell = 0 (as both metals are same )

 = emf of the cell = ?

Thus the cell potential will be 0.029 V