The pOH of a solution is 3.1. Which of the following is true about the solution? (1 point) It is acidic and has a pH of 10.9.

It is basic and has a pH of 10.9.

It is acidic and has a pH of 6.2.

It is basic and has a pH of 6.2.

Explanation:

To solve the question above we must first find the pH of the solution using the formula

pH + pOH = 14

pOH = 3.1

So we have

pH + 3.1 = 14

pH = 14 - 3.1

pH = 10.9

Since it's pH is 10.9 the solution is a basic solution since it's pH lies in the basic region.

Hope this helps you

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

i believe the answer is true.