A 135 g sample of H20 at 85°C is cooled. The water loses a total of 15 kJ of energy in the cooling process. What is the final temperature of the water? The specific heat of water is 4.184 J/g.°C.

A. 112°C

B. 58°C

C. 70°C

D. 84°C

E. 27°C

B. 58°C

Explanation:

Hello,

In this case, the relationship among heat, mass, specific heat and temperature for water is mathematically by:

In such a way, solving for the final temperature we obtain:

Therefore, we final temperature is computed as follows, considering that the involved heat is negative as it is lost for water:

Thereby, answer is B. 58°C .

Regards.

h let me think

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