Will the concentration of NO2 increase, decrease, or remain the same when the equilibrium NO2Cl(g)+NO(g)?NOCl(g)+NO2(g)is disturbed by the following events? Part A
Adding NOCl.
Adding .
[NO2] will increase.
[NO2] will decrease.
[NO2] will remain the same.
Part B
Adding NO.
Adding .
[NO2] will increase.
[NO2] will decrease.
[NO2] will remain the same.
Part C
Removing NO.
Removing .
[NO2] will increase.
[NO2] will decrease.
[NO2] will remain the same.
Part D
Adding NO2Cl; also account for the change using the reaction quotient Qc.
Adding ; also account for the change using the reaction quotient .
[NO2] will increase.
[NO2] will decrease.
[NO2] will remain the same.

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years

c- cold periods in earth's history during which glaciers covered much of the surface.

explanation:

so what is the problem with your lab report and whats the subject of the lab report? i will you

its b it was a compound