SUPPLEMENTARY QUESTION 1. Calculate the amount of heat (in calories) absorbed when 50 g of water at 20°C spreads over your skin and
warms to body temperature, 370C?

850 Calories.

Explanation:

The following data were obtained from the question:

Mass (M) = 50 g

Initial temperature (T1) = 20 °C

Final temperature (T2) = 37 °C

Specific heat capacity (C) of water = 1 cal/g°C

Heat absorbed (Q) =..?

Next, we shall determine the change in temperature of water.

This can be obtained as follow:

Initial temperature (T1) = 20 °C

Final temperature (T2) = 37 °C

Change in temperature (ΔT) =..?

Change in temperature (ΔT) = T2 – T1

Change in temperature (ΔT) = 37 – 20

Change in temperature (ΔT) = 17 °C

Finally, we shall determine the heat absorbed. This can be obtained as follow:

Mass (M) = 50 g

Specific heat capacity (C) of water = 1 cal/g°C.

Change in temperature (ΔT) = 17 °C

Heat absorbed (Q) =..?

Q = MCΔT

Q = 50 x 1 x 17

Q = 850 Calories

Therefore, the heat absorbed is 850 Calories.

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