Find the H+ and (OH)- concentrations in 0.01M KOH

Explanation:

KOH will split as follows

KOH      ⇄      K⁺   +   OH⁻

KOH is a strong base so it will split 100 %

.01 M              .01          .01

concentration of OH⁻  = .01 gm ion / litre

[ OH⁻ ]  = .01 = 10⁻² M

[ H⁺ ] [ OH⁻ ] = 10⁻¹⁴

[ H⁺ ]  x 10⁻² = 10⁻¹⁴

[ H⁺ ] = 10⁻¹² M .

it takes on an electronical energy