What is the correct formula for the Ksp of the reaction MgF2(s) – Mg2+ (aq) + 2F (aq)? Ksp = [Mg2+][F]
Ksp =[Mg2+][F]2
Ksp = 2[Mg2+][F]
Ksp = [Mg2+][F]

Ksp = [Mg₂⁺][F⁻]²

Explanation:

Ksp is the equilibrium constant for a solid dissolving in an aqueous solution. The equilibrium constant for a reaction is always products over reactants.

MgF₂ (s) ⇒ Mg₂⁺(aq) + 2F⁻(aq)

The equilibrium constant would be K = [Mg₂⁺][F⁻]². Since MgF₂ is solid, it is not included in the equilibrium expression.

Therefore, Ksp would be the same as the equilibrium constant.

Ksp = [Mg₂⁺][F⁻]²

Hope this helps.

it is b that is the answer.