To what volume will a 2.33 L sample of gas expand if it is heated from 10.0°C to 100.0°C? Group of answer choices 0.233 L 4.41 L 23.3 L 3.76 L 3.07 L

3.07 L

Explanation:

This question describes Charles law, which shows the direct relationship of the absolute temperature to its volume when the pressure is kept constant. The Charles' law equation is:

V1/T1 = V2/T2

Where; V1 is the volume of the gas at an initial state

V2 is the volume of the gas at a final state

T1 is the absolute temperature of the gas at an initial state

T2 is the absolute temperature of the gas at a final state.

According to the question, V1 = 2.33L, V2 = ?, T1 = 10°C, T2 = 100°C

The absolute temperature unit, which is Kelvin, need to be used. Hence, we convert °C to Kelvin using:

T(K) = T(°C) + 273.15

T1 (K) = 10°C + 273.15 = 283.15K

T2 (K) = 100°C + 273.15 = 373.15K

To solve for V2 in the above Charles law equation, we make V2 the subject of the formula by saying:

V2 = V1 × T2 / T1

V2 = 2.33 × 373.15 / 283.15

V2 = 869.4395/ 283.15

V2 = 3.0705

Hence, the gas will be expanded to a volume of 3.07L when heated from 10.0°C to 100.0°C.

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.