If the value of Kp for N2+3H2...2NH3 is 4/27, then for which of following reaction the value of Kp is reciprocal of above reaction: A. 2SO2+O2...2SO3 B. N2O4...2NO2 C. 2O3...3O2 D. PCI5...PCL3+CL2

C. 2O₃ ⇌ 3O₂

Explanation:

Kp is the equilibrium constant calculated from the partial pressures of a gas-phase reaction equation.

For a general gas-phase reaction aA + bB ⇌ nC + xD

the expression for the Kp = (pC)ⁿ(pD)ˣ / (pA)ᵃ(pB)ᵇ

where pA = partial pressure of A; pB = partial pressure of B; pC = partial pressure of C; pD = partial pressure of D

From the given reaction in equilibrium;  N₂ + 3H₂  ⇌ 2NH₃

Kp = (pNH₃)² / (pN₂)¹ * (pH₂)³ = 4/7

(pNH₃)² / (pN₂)¹ * (pH₂)³ = (2)²/ (1)¹ * (3)³

Therefore, number of mole of reactants and products is equivalent to partial pressure.

A. 2SO₂ ⇌ O₂ + 2SO₃

pSO₂ = 2, pO₂ = 1, pSO₃ = 2,

Kp =  2²/ (2² * 1²) = 4/4 = 1

B. N₂O₄ ⇌ 2NO₂

pN₂O₄ = 1, pNO₂ = 2

Kp = 2²/1² = 4

C. 2O₃ ⇌ 3O₂

pO₃ = 2, pO₂ = 3

Kp = 3³/2² = 27/4

D. PCl₅ ⇌ PCl₃ + Cl₂

pPCl₅ = 1, pPCl₃ = 1, pCl₂ = 1

Kp = (1¹ * 1¹) / 1¹ = 1

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation: