Chemistry, 21.07.2020 21:01 grace783

Consider the following intermediate chemical equations. 2
C(s)+102(g) → CO(g)
CO(g) + 2O2(g) –> C0,00)
How will oxygen appear in the final chemical equation?
O O2(g)
as a product
O2(g)
as a reactant
O(g) as a product
20 (9) as a reactant

Answers: 1

Show answers

Other questions on the subject: Chemistry

Chemistry, 21.06.2019 22:00, carlybeavers50

The graph above shows how the price of cell phones varies with the demand quantity. the equilibrium price for cell phones is where both supply and demand quantities equal $100, 5,000 5,000, $100

Answers: 2

continue

Chemistry, 22.06.2019 05:30, NorbxrtThaG

The table describes how some substances were formed substance 19 description formed by boiling pure water formed by combining three hydrogen atoms to every nitrogen atom formed by adding 5 g of sugar to 1 l of water formed by compressing carbon under high pressure based on the given descriptions, which substance is most likely a mixture?

Answers: 1

continue

Chemistry, 22.06.2019 09:50, Amandachavez94

Although respiratory organs vary across different organisms, they all contain respiratory surfaces that have a large surface area and are extremely thin. explain why having an extremely thin respiratory surface with a large surface area is advantageous for the process of gas exchange

Answers: 1

continue

Chemistry, 22.06.2019 12:30, pup88

According to the valence shell electron pair repulsion (vsepr) theory, a molecule that has four electron groups around the central atom will exhibit what electron geometry? view available hint(s) according to the valence shell electron pair repulsion (vsepr) theory, a molecule that has four electron groups around the central atom will exhibit what electron geometry? trigonal bipyramidal tetrahedral square planar determination of electron geometry requires information on whether the electron groups are lone pairs or bonding groups.

Answers: 2

continue

You know the right answer?

Consider the following intermediate chemical equations. 2
C(s)+102(g) → CO(g)
CO(g) + 2O2...